20-22y +6y²
tolong bantu saya![]()
tolong bantu saya
20 - 22y + 6y²
= 2(10 - 11y + 3y²)
= 2(3y² - 11y + 10)
= 2(3y² - 5y - 6y + 10)
= 2((3y² - 5y) + (-6y + 10))
= 2(y(3y - 5) - 2(3y - 5)
= 2(3y - 5) (y - 2)
6y²-22y+20 = 0
=> (6y-10)(y-2) = 0
maka y1 = 10/6 dan y2 = 2
[answer.2.content]
